10. Comparing Two Population Means
We have two populations and two sample sets, one from each population :
|Sample Mean||Sample std. dev.|
|From population 1|
|From population 2|
The population means are and and just as with the single population test, there are 3 possible hypothesis tests :
|Two Tailed||Right Tailed||Left Tailed|
In the second row the hypotheses are written in terms of a difference. Irrespective of which way you write the hypotheses, give population 1 priority. Write population 1 first. That way you won’t mess up your signs or your interpretation.
The test statistic to use, in all cases is
where = sample set size from population 1 and = sample set size from population 2. This test statistic is based on a distribution of sample means as shown in Figure 10.1.
Example 10.1 : A researcher hypothesizes that the average number of sports colleges offer for males is greater than the average number of sports offered for females. Samples of the number of sports offered to each sex by randomly selected colleges is given here :
|Males (pop. 1)||Females (pop. 2)|
At is there enough evidence to support the claim?
Note that () so is true on the face of it. If is not true on the face of it then is just plain false without the need for any statistical test. With the hypotheses direction set correctly, the question becomes: Is significantly greater than ? The term “statistically significant” corresponds to “reject “.
2. Critical statistic.
From the t Distribution Table, one-tailed test at we find
Note that is positive because this is a right-tailed test. For left tailed tests make negative. For two-tailed tests you have .
3. Test statistic.
Using the Standard Normal Distribution Table, we can find the -value. Since , .
Do not reject since is not in the rejection region. The -value reflects this :
There is not enough evidence, at under a -test, to support the claim that colleges offer more sports for males than females.
- You could specify a non-zero null hypothesis, e.g. , in which case you would have . We won't consider that case in this course. ↵